The L-R series circuit differential equation acted on by an electromotive force E sin(omega)t satisfies the differential equation L di/dt+Ri = E sin(omega)t. If there is no current in the circuit initially, obtain the value of current at any time ‘t’.

## Question

## Question

The L-R series circuit differential equation acted on by an electromotive force E sin(omega)t satisfies the differential equation L di/dt+Ri = E sin(omega)t. If there is no current in the circuit initially, obtain the value of current at any time ‘t’.

## Topic

Flow of Electricity in L-R circuits

## Problems of Flow of Electricity in L-R circuits

- A series circuit with resistance R, Inductance L and electromotive force E is governed by the differential equation L di/dt+Ri=E, where L and R are constants and initially the current ‘i’ is zero. Find the current at any time t
- An inductance 2 henry (H) and a resistance 20 ohms (Ω) are connected in series with emf E volts (V). If the current is initially zero when t=0, find the current at the end of 0.01 seconds if E=100V
- The L-R series circuit differential equation acted on by an electromotive force E sin(omega)t satisfies the differential equation L di/dt+Ri = E sin(omega)t. If there is no current in the circuit initially, obtain the value of current at any time ‘t’
- A voltage E e^ (-at) is applied at t=0 to a circuit of inductance L and resistance R. Show that the current at any time ‘t’ is E/(R-aL) [e^ (-at)-e^ (-Rt/L)] given that the current is initially zero when t=0